Re: Array question

Hi Dan,

> (from function/objects/Array.st):
>
> Array size_: _size value_: _value
> [
>     self := self new: (SmallInteger value_: _size).
>     _oops := _value.
>     {
>       int i;
>       for (i= 0;  i < (int)v__size;  ++i)
>         ((oop *)self->v__oops)[i]= *((oop **)v__value)[i];
>     }.
> ]

This is the constructor that the compiler invokes implicitly whenever  
you write an Array literal "#( ... )" in a program.  The argument  
_value points to a C array of oops corresponding to "..." in your  
constant and _size is an int reflecting the number of entries in the  
C array.

> What is that "_oops := _value." doing?

_oops is an instance variable of the receiver, which by line 2 is a  
new Arrray of size _size.  The line in question makes the C array  
containing "..." be the contents of the Array object.

Cheers,
Ian