Mugund K | 13 May 13:32

Re: sorting dictionary keys?

A quick but ugly [brain-dead :-) ]fix would be sorting keys seperately,
 
>>> for i in d.keys():
 print "%s\t%s" % (i, d[i])
 
 
a 1
c 0
b 3
d 2
>>> temp = d.keys()
>>> temp.sort()
>>> for i in temp:
 print "%s\t%s" % (i, d[i])
 
 
a 1
b 3
c 0
d 2
>>>
 
Thnx,
Mugund

--- On Tue, 5/13/08, James Hartley <jjhartley <at> gmail.com> wrote:
From: James Hartley <jjhartley <at> gmail.com>
Subject: [Tutor] sorting dictionary keys?
To: tutor <at> python.org
Date: Tuesday, May 13, 2008, 11:06 AM

I suspect this is a brain-dead question... Given the following code, output is as expected: $ cat test.py d = { 'a' : 1, 'd' : 2, 'b' : 3, 'c' : 0 } for i in d.keys(): print "%s\t%s" % (i, d[i]) $ python test.py a 1 c 0 b 3 d 2 $ But if the keys are sorted, I get an error: $ cat test1.py d = { 'a' : 1, 'd' : 2, 'b' : 3, 'c' : 0 } for i in d.keys().sort(): print "%s\t%s" % (i, d[i]) $ python test1.py Traceback (most recent call last): File "test.py", line 3, in <module> for i in d.keys().sort(): TypeError: 'NoneType' object is not iterable $ What is the correct manner to iterate through sorted dictionary keys? Thanks. Jim _______________________________________________ Tutor maillist - Tutor <at> python.org http://mail.python.org/mailman/listinfo/tutor

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Gmane