Re: Open a directory in the default file manager

Hi!

>  > is there any function/module that allows me to open a directory in the
>  > default file manager of a operating system?
> 
> On Windows you can use os.startfile().
> On "pure" Unices there's no such thing as filetype associations
> However, if you use a desktop environment, you can spawn xdg-open (from 
> xdg-utils) from Python. This will autodetect gnome, kde and xfce and use 
> their tools (gnome-open, kfmclient, exo-open).
> I think on OS X/Darwin there's a similar utility called `open'.
> 
> You can use sys.platform to determine which system you're running on.
I wasn't able to start explorer with os.startfile()

I then used
subprocess.call(['explorer', my_directory])

And it works.

Kind regards,
Timmie

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