Re: Re: [linuxjobs] Cypher: help requested

On Tue, 2004-06-01 at 17:39, Rich Walker wrote:
> Note that, since ITV contains no information, d(compressed)/dt is
> proportional to log(t):

Let's see.

dc/dt ~ ln(t)

dc/dt = a * ln(t)

c = at (ln(t) - 1) + C

Hmmm.  Don't think that helped.

John

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